JEE Marks Calculator
Calculate your NTA JEE Main raw score across Physics, Chemistry, and Mathematics using the official marking scheme (+4 for correct, -1 for incorrect responses).
| Subject | Score Obtained | Max Possible |
|---|---|---|
| Physics | 68 | 100 |
| Chemistry | 78 | 100 |
| Mathematics | 51 | 100 |
| Overall Composite | 197 | 300 |
Come funziona
Formula
Score = (Correct × 4) - (Incorrect × 1) Esempio pratico
With 18 correct and 4 incorrect in Physics (68 marks), 20 correct and 3 incorrect in Chemistry (77 marks), and 15 correct and 5 incorrect in Mathematics (55 marks), the total score is 200 out of 300.
Understanding NTA JEE Main Scoring
The Joint Entrance Examination (JEE Main), administered by the National Testing Agency (NTA), is the gateway for admission into National Institutes of Technology (NITs), Indian Institutes of Information Technology (IIITs), Centrally Funded Technical Institutions (CFTIs), and eligibility for JEE Advanced.
When the NTA releases the provisional answer keys and recorded response sheets, calculating your exact raw score helps you evaluate prospective percentile bands and anticipate college admissions.
Official NTA Exam Structure and Marking Pattern
JEE Main Paper 1 (B.E. / B.Tech) consists of three subject sections—Physics, Chemistry, and Mathematics:
| Section | Section A (MCQs) | Section B (Numerical) | To Attempt | Maximum Marks |
|---|---|---|---|---|
| Physics | 20 | 10 (Attempt any 5) | 25 | 100 |
| Chemistry | 20 | 10 (Attempt any 5) | 25 | 100 |
| Mathematics | 20 | 10 (Attempt any 5) | 25 | 100 |
| Total | 60 | 30 (Attempt 15) | 75 | 300 |
Scoring Rules
- Correct Answer: $+4$ marks
- Incorrect Answer: $-1$ mark (applied to both Section A MCQs and Section B Numerical questions)
- Unattempted / Dropped Questions: $0$ marks
The scoring formula for each section is:
$$\text{Section Score} = (\text{Correct} \times 4) - (\text{Incorrect} \times 1)$$
$$\text{Total Score} = \text{Score}{\text{Physics}} + \text{Score}{\text{Chemistry}} + \text{Score}_{\text{Mathematics}}$$
Detailed Worked Example
Suppose a candidate checks their answer sheet and records the following performance:
-
Physics:
- Correct: $18$
- Incorrect: $4$
- Marks: $(18 \times 4) - (4 \times 1) = 72 - 4 = \mathbf{68\text{ marks}}$
-
Chemistry:
- Correct: $20$
- Incorrect: $3$
- Marks: $(20 \times 4) - (3 \times 1) = 80 - 3 = \mathbf{77\text{ marks}}$
-
Mathematics:
- Correct: $15$
- Incorrect: $5$
- Marks: $(15 \times 4) - (5 \times 1) = 60 - 5 = \mathbf{55\text{ marks}}$
- Total Composite Score: $68 + 77 + 55 = \mathbf{200\text{ marks}}$ (out of 300).
A raw score of 200 marks in typical sessions corresponds to a 99.2 to 99.5+ NTA percentile, positioning the candidate well for top NITs (Trichy, Surathkal, Warangal) in Computer Science and Electronics.
Navigating Normalization and Tie-Breaking
Because JEE Main is administered over multiple shifts and days, NTA normalizes scores across shifts:
- Percentile scores measure the percentage of candidates in your specific shift who scored equal to or lower than you.
- Tie-breaking hierarchy: Higher percentile in Mathematics, followed by Physics, Chemistry, lower ratio of negative marks, and candidate age.
To calculate scores for the next stage, explore our jee advanced marks calculator, or check our gate calculator for graduate engineering admissions.
Domande frequenti
What is the official marking scheme for JEE Main?
Under current NTA regulations, candidates receive +4 marks for each correct response and -1 mark penalty for each incorrect response across both Multiple Choice Questions (MCQs) and Numerical Value Questions (NV).
Do numerical value questions have negative marking in JEE Main?
Yes. The National Testing Agency (NTA) enforces a -1 mark negative penalty for incorrect numerical answer questions in JEE Main.
What is the total marks possible in JEE Main Paper 1?
Paper 1 (B.E./B.Tech) comprises 75 attempted questions out of 90 (25 in Physics, 25 in Chemistry, 25 in Mathematics), yielding a maximum total score of 300 marks.
How is raw score converted into NTA percentile score?
NTA applies multi-session normalization based on candidate distribution: Percentile = 100 * (Number of candidates in the session with raw score <= candidate score) / (Total candidates who appeared in that session).
What marks are typically needed to qualify for JEE Advanced?
While cutoffs fluctuate depending on session difficulty, general category qualifying cutoffs typically range between 88 and 93 percentile (~80 to 95 marks out of 300).